Tuesday, April 15, 2008
Mathematics may be defined as the subject in which we never know what we are talking about, nor whether what we are saying is true.
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and not realy a math joke, more of just a school joke, why is it always Murphys law and never Ockams razor. my boss is out today and everything is breaking down.
here's a little math brain teaser I came across recently
Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
one in two. now, i know that is not correct, or else this would not be a trick question. i will ponder and get back.
wait, you say 1, he opens 3 and asks to open 2. the car is obviously behiond 1 which he will not open.
you should switch because you have a 1/3 chance of getting it the 1st time, and a 2/3 chance if you switch.
The Monty Hall Problem is classic.
most would say the your chance of choosing correctly the second time is 1 in 2, but if you break it down, your chance of choosing correctly is actually 2 in 3, so your odds are better if you switch.
most would say the your chance of choosing correctly the second time is 1 in 2, but if you break it down, your chance of choosing correctly is actually 2 in 3, so your odds are better if you switch.
I still think that no matter what the odds are, your still getting the goat. I've never trusted Monty Hall.
now many have argued that the odds the second time are still only 1 in 2, no matter what happened the first time you chose, because it is now a new problem with only two doors.
I'm not sure that I care which is the correct answer, but I did find it an interesting question
I'm not sure that I care which is the correct answer, but I did find it an interesting question
I believe that if we apply Occam's Razor, it would have to be the 1 in 2 answer, the whole easiest answer is the correct answer thing
the true Monty Hall Problem is did you have better odds of getting chosen to participate if you dressed as little bo beep or as little red riding hood?
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